Base | Representation |
---|---|
bin | 1011111100010101001110… |
… | …1111100100100000011001 |
3 | 1201111022201022220211022111 |
4 | 2333011103233210200121 |
5 | 3210120013210044342 |
6 | 43532204145152321 |
7 | 2523456252263035 |
oct | 277052357444031 |
9 | 51438638824274 |
10 | 13131120003097 |
11 | 4202970a06818 |
12 | 1580a9562b6a1 |
13 | 74334a8c5575 |
14 | 33579a1591c5 |
15 | 17b8859d3217 |
hex | bf153be4819 |
13131120003097 has 2 divisors, whose sum is σ = 13131120003098. Its totient is φ = 13131120003096.
The previous prime is 13131120003077. The next prime is 13131120003137. The reversal of 13131120003097 is 79030002113131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7264943966736 + 5866176036361 = 2695356^2 + 2422019^2 .
It is a cyclic number.
It is not a de Polignac number, because 13131120003097 - 27 = 13131120002969 is a prime.
It is not a weakly prime, because it can be changed into another prime (13131120003077) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565560001548 + 6565560001549.
It is an arithmetic number, because the mean of its divisors is an integer number (6565560001549).
Almost surely, 213131120003097 is an apocalyptic number.
It is an amenable number.
13131120003097 is a deficient number, since it is larger than the sum of its proper divisors (1).
13131120003097 is an equidigital number, since it uses as much as digits as its factorization.
13131120003097 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3402, while the sum is 31.
The spelling of 13131120003097 in words is "thirteen trillion, one hundred thirty-one billion, one hundred twenty million, three thousand, ninety-seven".
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