Base | Representation |
---|---|
bin | 11000011101010110… |
… | …10000011010001101 |
3 | 1020220010112010110121 |
4 | 30032223100122031 |
5 | 203343031403232 |
6 | 10010553304541 |
7 | 643254461305 |
oct | 141653203215 |
9 | 36803463417 |
10 | 13131122317 |
11 | 56291a3605 |
12 | 2665705151 |
13 | 13135c1281 |
14 | 8c7d3c605 |
15 | 51cc02d97 |
hex | 30ead068d |
13131122317 has 2 divisors, whose sum is σ = 13131122318. Its totient is φ = 13131122316.
The previous prime is 13131122287. The next prime is 13131122327. The reversal of 13131122317 is 71322113131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9100015236 + 4031107081 = 95394^2 + 63491^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13131122317 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13131122291 and 13131122300.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13131122327) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565561158 + 6565561159.
It is an arithmetic number, because the mean of its divisors is an integer number (6565561159).
Almost surely, 213131122317 is an apocalyptic number.
It is an amenable number.
13131122317 is a deficient number, since it is larger than the sum of its proper divisors (1).
13131122317 is an equidigital number, since it uses as much as digits as its factorization.
13131122317 is an evil number, because the sum of its binary digits is even.
The product of its digits is 756, while the sum is 25.
Adding to 13131122317 its reverse (71322113131), we get a palindrome (84453235448).
The spelling of 13131122317 in words is "thirteen billion, one hundred thirty-one million, one hundred twenty-two thousand, three hundred seventeen".
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