Base | Representation |
---|---|
bin | 11101110110110101000110… |
… | …111011101111000110000101 |
3 | 122012221020020001120020120221 |
4 | 131312311012323233012011 |
5 | 114202400342123031000 |
6 | 1143135313304424341 |
7 | 36441631400101540 |
oct | 3566650673570605 |
9 | 565836201506527 |
10 | 131311225205125 |
11 | 38926861396149 |
12 | 12888bb37780b1 |
13 | 5836798147924 |
14 | 245d6d64bb857 |
15 | 102aa8dbe561a |
hex | 776d46eef185 |
131311225205125 has 32 divisors (see below), whose sum is σ = 191642843867904. Its totient is φ = 87947983368000.
The previous prime is 131311225205119. The next prime is 131311225205131. The reversal of 131311225205125 is 521502522113131.
It is an interprime number because it is at equal distance from previous prime (131311225205119) and next prime (131311225205131).
It is not a de Polignac number, because 131311225205125 - 217 = 131311225074053 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1744962046 + ... + 1745037295.
It is an arithmetic number, because the mean of its divisors is an integer number (5988838870872).
Almost surely, 2131311225205125 is an apocalyptic number.
It is an amenable number.
131311225205125 is a deficient number, since it is larger than the sum of its proper divisors (60331618662779).
131311225205125 is an equidigital number, since it uses as much as digits as its factorization.
131311225205125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3489999406 (or 3489999396 counting only the distinct ones).
The product of its (nonzero) digits is 18000, while the sum is 34.
Adding to 131311225205125 its reverse (521502522113131), we get a palindrome (652813747318256).
The spelling of 131311225205125 in words is "one hundred thirty-one trillion, three hundred eleven billion, two hundred twenty-five million, two hundred five thousand, one hundred twenty-five".
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