13131123000000 has 392 divisors, whose sum is σ = 45982658601936. Its totient is φ = 3295641600000.

The previous prime is 13131122999999. The next prime is 13131123000011. The reversal of 13131123000000 is 32113131.

It is a super-2 number, since 2×13131123000000² (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a polite number, since it can be written in 55 ways as a sum of consecutive naturals, for example, 50871264 + ... + 51128736.

Almost surely, 2^{13131123000000} is an apocalyptic number.

13131123000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13131123000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (22991329300968).

13131123000000 is an abundant number, since it is smaller than the sum of its proper divisors (32851535601936).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13131123000000 is an frugal number, since it uses more digits than its factorization.

13131123000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 257535 (or 257500 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 13131123000000 its reverse (32113131), we get a palindrome (13131155113131).

The spelling of 13131123000000 in words is "thirteen trillion, one hundred thirty-one billion, one hundred twenty-three million", and thus it is an aban number.