Base | Representation |
---|---|
bin | 11101110110110101001100… |
… | …110001101011011101001001 |
3 | 122012221020110220000112021122 |
4 | 131312311030301223131021 |
5 | 114202401042221411243 |
6 | 1143135331125445025 |
7 | 36441634000235435 |
oct | 3566651461533511 |
9 | 565836426015248 |
10 | 131311323232073 |
11 | 3892690175a256 |
12 | 12889020570775 |
13 | 58367b254a33a |
14 | 245d7055179c5 |
15 | 102aa9760a668 |
hex | 776d4cc6b749 |
131311323232073 has 2 divisors, whose sum is σ = 131311323232074. Its totient is φ = 131311323232072.
The previous prime is 131311323232069. The next prime is 131311323232079. The reversal of 131311323232073 is 370232323113131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 93980848474384 + 37330474757689 = 9694372^2 + 6109867^2 .
It is a cyclic number.
It is not a de Polignac number, because 131311323232073 - 22 = 131311323232069 is a prime.
It is not a weakly prime, because it can be changed into another prime (131311323232079) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65655661616036 + 65655661616037.
It is an arithmetic number, because the mean of its divisors is an integer number (65655661616037).
Almost surely, 2131311323232073 is an apocalyptic number.
It is an amenable number.
131311323232073 is a deficient number, since it is larger than the sum of its proper divisors (1).
131311323232073 is an equidigital number, since it uses as much as digits as its factorization.
131311323232073 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 40824, while the sum is 35.
The spelling of 131311323232073 in words is "one hundred thirty-one trillion, three hundred eleven billion, three hundred twenty-three million, two hundred thirty-two thousand, seventy-three".
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