Base | Representation |
---|---|
bin | 11101110110110101001100… |
… | …110001101011011101001111 |
3 | 122012221020110220000112021212 |
4 | 131312311030301223131033 |
5 | 114202401042221411304 |
6 | 1143135331125445035 |
7 | 36441634000235444 |
oct | 3566651461533517 |
9 | 565836426015255 |
10 | 131311323232079 |
11 | 3892690175a261 |
12 | 1288902057077b |
13 | 58367b254a343 |
14 | 245d7055179cb |
15 | 102aa9760a66e |
hex | 776d4cc6b74f |
131311323232079 has 2 divisors, whose sum is σ = 131311323232080. Its totient is φ = 131311323232078.
The previous prime is 131311323232073. The next prime is 131311323232121. The reversal of 131311323232079 is 970232323113131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131311323232079 is a prime.
It is a super-2 number, since 2×1313113232320792 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131311323232073) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65655661616039 + 65655661616040.
It is an arithmetic number, because the mean of its divisors is an integer number (65655661616040).
Almost surely, 2131311323232079 is an apocalyptic number.
131311323232079 is a deficient number, since it is larger than the sum of its proper divisors (1).
131311323232079 is an equidigital number, since it uses as much as digits as its factorization.
131311323232079 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 122472, while the sum is 41.
The spelling of 131311323232079 in words is "one hundred thirty-one trillion, three hundred eleven billion, three hundred twenty-three million, two hundred thirty-two thousand, seventy-nine".
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