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131311323232079 is a prime number
BaseRepresentation
bin11101110110110101001100…
…110001101011011101001111
3122012221020110220000112021212
4131312311030301223131033
5114202401042221411304
61143135331125445035
736441634000235444
oct3566651461533517
9565836426015255
10131311323232079
113892690175a261
121288902057077b
1358367b254a343
14245d7055179cb
15102aa9760a66e
hex776d4cc6b74f

131311323232079 has 2 divisors, whose sum is σ = 131311323232080. Its totient is φ = 131311323232078.

The previous prime is 131311323232073. The next prime is 131311323232121. The reversal of 131311323232079 is 970232323113131.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131311323232079 is a prime.

It is a super-2 number, since 2×1313113232320792 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131311323232073) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65655661616039 + 65655661616040.

It is an arithmetic number, because the mean of its divisors is an integer number (65655661616040).

Almost surely, 2131311323232079 is an apocalyptic number.

131311323232079 is a deficient number, since it is larger than the sum of its proper divisors (1).

131311323232079 is an equidigital number, since it uses as much as digits as its factorization.

131311323232079 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 122472, while the sum is 41.

The spelling of 131311323232079 in words is "one hundred thirty-one trillion, three hundred eleven billion, three hundred twenty-three million, two hundred thirty-two thousand, seventy-nine".