1313113232321 has 4 divisors (see below), whose sum is σ = 1432487162544. Its totient is φ = 1193739302100.

The previous prime is 1313113232311. The next prime is 1313113232323. The reversal of 1313113232321 is 1232323113131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1313113232321 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1313113232323) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59686965095 + ... + 59686965116.

It is an arithmetic number, because the mean of its divisors is an integer number (358121790636).

Almost surely, 2^{1313113232321} is an apocalyptic number.

1313113232321 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

1313113232321 is a deficient number, since it is larger than the sum of its proper divisors (119373930223).

1313113232321 is a wasteful number, since it uses less digits than its factorization.

1313113232321 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 119373930222.

The product of its digits is 1944, while the sum is 26.

Adding to 1313113232321 its reverse (1232323113131), we get a palindrome (2545436345452).

The spelling of 1313113232321 in words is "one trillion, three hundred thirteen billion, one hundred thirteen million, two hundred thirty-two thousand, three hundred twenty-one".