Base | Representation |
---|---|
bin | 11101110110110101111101… |
… | …101100101101011011100111 |
3 | 122012221022121002110112002101 |
4 | 131312311331230231123213 |
5 | 114202404232331404111 |
6 | 1143135544405552531 |
7 | 36441663224613022 |
oct | 3566657554553347 |
9 | 565838532415071 |
10 | 131312144013031 |
11 | 38927192aa4123 |
12 | 1288920b415747 |
13 | 58368b35c7c47 |
14 | 245d7825321b9 |
15 | 102aae46d9bc1 |
hex | 776d7db2d6e7 |
131312144013031 has 2 divisors, whose sum is σ = 131312144013032. Its totient is φ = 131312144013030.
The previous prime is 131312144013019. The next prime is 131312144013047. The reversal of 131312144013031 is 130310441213131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131312144013031 - 215 = 131312143980263 is a prime.
It is a super-2 number, since 2×1313121440130312 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131312144013931) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65656072006515 + 65656072006516.
It is an arithmetic number, because the mean of its divisors is an integer number (65656072006516).
Almost surely, 2131312144013031 is an apocalyptic number.
131312144013031 is a deficient number, since it is larger than the sum of its proper divisors (1).
131312144013031 is an equidigital number, since it uses as much as digits as its factorization.
131312144013031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 28.
Adding to 131312144013031 its reverse (130310441213131), we get a palindrome (261622585226162).
The spelling of 131312144013031 in words is "one hundred thirty-one trillion, three hundred twelve billion, one hundred forty-four million, thirteen thousand, thirty-one".
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