Base | Representation |
---|---|
bin | 10011000110111100101… |
… | …010001110011111100111 |
3 | 11122112102022011022000111 |
4 | 103012330222032133213 |
5 | 133003242313230203 |
6 | 2443124345353451 |
7 | 163604406426661 |
oct | 23067452163747 |
9 | 4575368138014 |
10 | 1313130211303 |
11 | 466993853299 |
12 | 1925b0798887 |
13 | 96a9b459b41 |
14 | 477ad32b531 |
15 | 242569e826d |
hex | 131bca8e7e7 |
1313130211303 has 2 divisors, whose sum is σ = 1313130211304. Its totient is φ = 1313130211302.
The previous prime is 1313130211291. The next prime is 1313130211369. The reversal of 1313130211303 is 3031120313131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1313130211303 - 25 = 1313130211271 is a prime.
It is a super-2 number, since 2×13131302113032 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1313130211373) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656565105651 + 656565105652.
It is an arithmetic number, because the mean of its divisors is an integer number (656565105652).
Almost surely, 21313130211303 is an apocalyptic number.
1313130211303 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313130211303 is an equidigital number, since it uses as much as digits as its factorization.
1313130211303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 486, while the sum is 22.
Adding to 1313130211303 its reverse (3031120313131), we get a palindrome (4344250524434).
The spelling of 1313130211303 in words is "one trillion, three hundred thirteen billion, one hundred thirty million, two hundred eleven thousand, three hundred three".
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