Base | Representation |
---|---|
bin | 1011111100010101111010… |
… | …0110011000000001110011 |
3 | 1201111100012000122110000021 |
4 | 2333011132212120001303 |
5 | 3210120401322021232 |
6 | 43532234213104311 |
7 | 2523463623400324 |
oct | 277053646300163 |
9 | 51440160573007 |
10 | 13131302142067 |
11 | 4202a547aa49a |
12 | 1580b26628097 |
13 | 743379567bc5 |
14 | 3357b640c44b |
15 | 17b8969b0397 |
hex | bf15e998073 |
13131302142067 has 2 divisors, whose sum is σ = 13131302142068. Its totient is φ = 13131302142066.
The previous prime is 13131302141999. The next prime is 13131302142097. The reversal of 13131302142067 is 76024120313131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13131302142067 - 219 = 13131301617779 is a prime.
It is not a weakly prime, because it can be changed into another prime (13131302142097) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565651071033 + 6565651071034.
It is an arithmetic number, because the mean of its divisors is an integer number (6565651071034).
Almost surely, 213131302142067 is an apocalyptic number.
13131302142067 is a deficient number, since it is larger than the sum of its proper divisors (1).
13131302142067 is an equidigital number, since it uses as much as digits as its factorization.
13131302142067 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18144, while the sum is 34.
Adding to 13131302142067 its reverse (76024120313131), we get a palindrome (89155422455198).
The spelling of 13131302142067 in words is "thirteen trillion, one hundred thirty-one billion, three hundred two million, one hundred forty-two thousand, sixty-seven".
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