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131313113003 = 671959897209
BaseRepresentation
bin111101001001011011…
…1110001011110101011
3110112221102210022000202
41322102313301132223
54122412124104003
6140154023422415
712326030021102
oct1722267613653
9415842708022
10131313113003
1150764913396
12215485b4a0b
13c4c8c51287
1464d9a41039
153638294088
hex1e92df17ab

131313113003 has 4 divisors (see below), whose sum is σ = 133273010280. Its totient is φ = 129353215728.

The previous prime is 131313112999. The next prime is 131313113021. The reversal of 131313113003 is 300311313131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131313113003 - 22 = 131313112999 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131313113053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 979948538 + ... + 979948671.

It is an arithmetic number, because the mean of its divisors is an integer number (33318252570).

Almost surely, 2131313113003 is an apocalyptic number.

131313113003 is a deficient number, since it is larger than the sum of its proper divisors (1959897277).

131313113003 is an equidigital number, since it uses as much as digits as its factorization.

131313113003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1959897276.

The product of its (nonzero) digits is 243, while the sum is 20.

Adding to 131313113003 its reverse (300311313131), we get a palindrome (431624426134).

The spelling of 131313113003 in words is "one hundred thirty-one billion, three hundred thirteen million, one hundred thirteen thousand, three".

Divisors: 1 67 1959897209 131313113003