Base | Representation |
---|---|
bin | 11101110110110110111101… |
… | …001111001111110001100111 |
3 | 122012221102100101100212010001 |
4 | 131312312331033033301213 |
5 | 114202413423231444312 |
6 | 1143140242250242131 |
7 | 36442031520614521 |
oct | 3566667517176147 |
9 | 565842311325101 |
10 | 131313210031207 |
11 | 3892768a809386 |
12 | 12889468426347 |
13 | 5836a2340b429 |
14 | 245d843d46a11 |
15 | 102ab580ac057 |
hex | 776dbd3cfc67 |
131313210031207 has 2 divisors, whose sum is σ = 131313210031208. Its totient is φ = 131313210031206.
The previous prime is 131313210031189. The next prime is 131313210031271. The reversal of 131313210031207 is 702130012313131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131313210031207 - 27 = 131313210031079 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131313210031907) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65656605015603 + 65656605015604.
It is an arithmetic number, because the mean of its divisors is an integer number (65656605015604).
Almost surely, 2131313210031207 is an apocalyptic number.
131313210031207 is a deficient number, since it is larger than the sum of its proper divisors (1).
131313210031207 is an equidigital number, since it uses as much as digits as its factorization.
131313210031207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2268, while the sum is 28.
Adding to 131313210031207 its reverse (702130012313131), we get a palindrome (833443222344338).
The spelling of 131313210031207 in words is "one hundred thirty-one trillion, three hundred thirteen billion, two hundred ten million, thirty-one thousand, two hundred seven".
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