Base | Representation |
---|---|
bin | 11101110110110110111101… |
… | …010111001110001110110111 |
3 | 122012221102100112022002012021 |
4 | 131312312331113032032313 |
5 | 114202413424300401124 |
6 | 1143140242403134011 |
7 | 36442031544443323 |
oct | 3566667527161667 |
9 | 565842315262167 |
10 | 131313212122039 |
11 | 38927690a07242 |
12 | 12889469074307 |
13 | 5836a23990ccc |
14 | 245d84432c983 |
15 | 102ab583717e4 |
hex | 776dbd5ce3b7 |
131313212122039 has 2 divisors, whose sum is σ = 131313212122040. Its totient is φ = 131313212122038.
The previous prime is 131313212122031. The next prime is 131313212122067. The reversal of 131313212122039 is 930221212313131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131313212122039 - 23 = 131313212122031 is a prime.
It is a super-2 number, since 2×1313132121220392 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 131313212121995 and 131313212122013.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131313212122031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65656606061019 + 65656606061020.
It is an arithmetic number, because the mean of its divisors is an integer number (65656606061020).
Almost surely, 2131313212122039 is an apocalyptic number.
131313212122039 is a deficient number, since it is larger than the sum of its proper divisors (1).
131313212122039 is an equidigital number, since it uses as much as digits as its factorization.
131313212122039 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11664, while the sum is 34.
The spelling of 131313212122039 in words is "one hundred thirty-one trillion, three hundred thirteen billion, two hundred twelve million, one hundred twenty-two thousand, thirty-nine".
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