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13131333312631 is a prime number
BaseRepresentation
bin1011111100010110000001…
…1101010010000001110111
31201111100021012022001222121
42333011200131102001313
53210120432312001011
643532241245140411
72523464452342522
oct277054035220167
951440235261877
1013131333312631
114202a7035a396
121580b34b5a707
13743382b5c921
143357ba603bb9
1517b8995bae71
hexbf160752077

13131333312631 has 2 divisors, whose sum is σ = 13131333312632. Its totient is φ = 13131333312630.

The previous prime is 13131333312589. The next prime is 13131333312649. The reversal of 13131333312631 is 13621333313131.

13131333312631 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13131333312631 - 235 = 13096973574263 is a prime.

It is a super-2 number, since 2×131313333126312 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13131333312931) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565666656315 + 6565666656316.

It is an arithmetic number, because the mean of its divisors is an integer number (6565666656316).

Almost surely, 213131333312631 is an apocalyptic number.

13131333312631 is a deficient number, since it is larger than the sum of its proper divisors (1).

13131333312631 is an equidigital number, since it uses as much as digits as its factorization.

13131333312631 is an evil number, because the sum of its binary digits is even.

The product of its digits is 26244, while the sum is 34.

Adding to 13131333312631 its reverse (13621333313131), we get a palindrome (26752666625762).

The spelling of 13131333312631 in words is "thirteen trillion, one hundred thirty-one billion, three hundred thirty-three million, three hundred twelve thousand, six hundred thirty-one".