Base | Representation |
---|---|
bin | 10011000110111100111… |
… | …001101111111010101011 |
3 | 11122112102120211000201102 |
4 | 103012330321233322223 |
5 | 133003244333432423 |
6 | 2443125012512015 |
7 | 163604456135063 |
oct | 23067471577253 |
9 | 4575376730642 |
10 | 1313134280363 |
11 | 466996082454 |
12 | 1925b201b60b |
13 | 96a9c252c79 |
14 | 477adaaa3a3 |
15 | 2425704dc28 |
hex | 131bce6feab |
1313134280363 has 2 divisors, whose sum is σ = 1313134280364. Its totient is φ = 1313134280362.
The previous prime is 1313134280309. The next prime is 1313134280401. The reversal of 1313134280363 is 3630824313131.
It is an a-pointer prime, because the next prime (1313134280401) can be obtained adding 1313134280363 to its sum of digits (38).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1313134280363 - 226 = 1313067171499 is a prime.
It is a super-3 number, since 3×13131342803633 (a number of 37 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (1313134280063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656567140181 + 656567140182.
It is an arithmetic number, because the mean of its divisors is an integer number (656567140182).
Almost surely, 21313134280363 is an apocalyptic number.
1313134280363 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313134280363 is an equidigital number, since it uses as much as digits as its factorization.
1313134280363 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 93312, while the sum is 38.
Adding to 1313134280363 its reverse (3630824313131), we get a palindrome (4943958593494).
The spelling of 1313134280363 in words is "one trillion, three hundred thirteen billion, one hundred thirty-four million, two hundred eighty thousand, three hundred sixty-three".
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