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13131366602451 = 34377122200817
BaseRepresentation
bin1011111100010110001001…
…1100010001011011010011
31201111100100111221101000220
42333011202130101123103
53210121014322234301
643532244434444123
72523465335322426
oct277054234213323
951440314841026
1013131366602451
114202a88127539
121580b44133643
13743389a17146
143357c0bcb9bd
1517b89c494936
hexbf1627116d3

13131366602451 has 4 divisors (see below), whose sum is σ = 17508488803272. Its totient is φ = 8754244401632.

The previous prime is 13131366602447. The next prime is 13131366602461. The reversal of 13131366602451 is 15420666313131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13131366602451 - 22 = 13131366602447 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13131366602461) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2188561100406 + ... + 2188561100411.

It is an arithmetic number, because the mean of its divisors is an integer number (4377122200818).

Almost surely, 213131366602451 is an apocalyptic number.

13131366602451 is a deficient number, since it is larger than the sum of its proper divisors (4377122200821).

13131366602451 is an equidigital number, since it uses as much as digits as its factorization.

13131366602451 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4377122200820.

The product of its (nonzero) digits is 233280, while the sum is 42.

The spelling of 13131366602451 in words is "thirteen trillion, one hundred thirty-one billion, three hundred sixty-six million, six hundred two thousand, four hundred fifty-one".

Divisors: 1 3 4377122200817 13131366602451