Base | Representation |
---|---|
bin | 1011111100010110011001… |
… | …0011100101000011100111 |
3 | 1201111100112000221002000222 |
4 | 2333011212103211003213 |
5 | 3210121132421314143 |
6 | 43532255112154555 |
7 | 2523500053344203 |
oct | 277054623450347 |
9 | 51440460832028 |
10 | 13131431432423 |
11 | 4203010787227 |
12 | 1580b61998a5b |
13 | 74339a295685 |
14 | 3357c9665b03 |
15 | 17b8a2eed768 |
hex | bf1664e50e7 |
13131431432423 has 2 divisors, whose sum is σ = 13131431432424. Its totient is φ = 13131431432422.
The previous prime is 13131431432389. The next prime is 13131431432437. The reversal of 13131431432423 is 32423413413131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13131431432423 - 28 = 13131431432167 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13131431432123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565715716211 + 6565715716212.
It is an arithmetic number, because the mean of its divisors is an integer number (6565715716212).
Almost surely, 213131431432423 is an apocalyptic number.
13131431432423 is a deficient number, since it is larger than the sum of its proper divisors (1).
13131431432423 is an equidigital number, since it uses as much as digits as its factorization.
13131431432423 is an evil number, because the sum of its binary digits is even.
The product of its digits is 62208, while the sum is 35.
Adding to 13131431432423 its reverse (32423413413131), we get a palindrome (45554844845554).
The spelling of 13131431432423 in words is "thirteen trillion, one hundred thirty-one billion, four hundred thirty-one million, four hundred thirty-two thousand, four hundred twenty-three".
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