Base | Representation |
---|---|
bin | 1011111100010110101101… |
… | …0000100000101010110101 |
3 | 1201111100201211021001200011 |
4 | 2333011223100200222311 |
5 | 3210121320203422401 |
6 | 43532311241020221 |
7 | 2523502112463634 |
oct | 277055320405265 |
9 | 51440654231604 |
10 | 13131514514101 |
11 | 4203053672775 |
12 | 1580b85784671 |
13 | 7433b1564629 |
14 | 3357d66d151b |
15 | 17b8aa460451 |
hex | bf16b420ab5 |
13131514514101 has 2 divisors, whose sum is σ = 13131514514102. Its totient is φ = 13131514514100.
The previous prime is 13131514514039. The next prime is 13131514514117. The reversal of 13131514514101 is 10141541513131.
13131514514101 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10644982902225 + 2486531611876 = 3262665^2 + 1576874^2 .
It is a cyclic number.
It is not a de Polignac number, because 13131514514101 - 225 = 13131480959669 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13131514514161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565757257050 + 6565757257051.
It is an arithmetic number, because the mean of its divisors is an integer number (6565757257051).
Almost surely, 213131514514101 is an apocalyptic number.
It is an amenable number.
13131514514101 is a deficient number, since it is larger than the sum of its proper divisors (1).
13131514514101 is an equidigital number, since it uses as much as digits as its factorization.
13131514514101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3600, while the sum is 31.
The spelling of 13131514514101 in words is "thirteen trillion, one hundred thirty-one billion, five hundred fourteen million, five hundred fourteen thousand, one hundred one".
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