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13131521040342 = 2314091553290873
BaseRepresentation
bin1011111100010110101110…
…1001011001111111010110
31201111100202021112121222210
42333011223221121333112
53210121323341242332
643532312032534250
72523502222114605
oct277055351317726
951440667477883
1013131521040342
11420305731aa61
121580b879b1386
137433b2a0b003
143357d750da3c
1517b8aacedecc
hexbf16ba59fd6

13131521040342 has 16 divisors (see below), whose sum is σ = 26281681588080. Its totient is φ = 4374067095552.

The previous prime is 13131521040317. The next prime is 13131521040367. The reversal of 13131521040342 is 24304012513131.

It is an interprime number because it is at equal distance from previous prime (13131521040317) and next prime (13131521040367).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 776636983 + ... + 776653890.

It is an arithmetic number, because the mean of its divisors is an integer number (1642605099255).

Almost surely, 213131521040342 is an apocalyptic number.

13131521040342 is an abundant number, since it is smaller than the sum of its proper divisors (13150160547738).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13131521040342 is a wasteful number, since it uses less digits than its factorization.

13131521040342 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1553292287.

The product of its (nonzero) digits is 8640, while the sum is 30.

Adding to 13131521040342 its reverse (24304012513131), we get a palindrome (37435533553473).

The spelling of 13131521040342 in words is "thirteen trillion, one hundred thirty-one billion, five hundred twenty-one million, forty thousand, three hundred forty-two".

Divisors: 1 2 3 6 1409 2818 4227 8454 1553290873 3106581746 4659872619 9319745238 2188586840057 4377173680114 6565760520171 13131521040342