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131320000000 = 29577267
BaseRepresentation
bin111101001001101001…
…0000010111000000000
3110112221220202012012201
41322103102002320000
54122420410000000
6140154431202544
712326142403600
oct1722322027000
9415856665181
10131320000000
1150768797722
122154a976454
13c4ca4c2c17
1464da914c00
153638ba496a
hex1e93482e00

131320000000 has 480 divisors, whose sum is σ = 387220493088. Its totient is φ = 44352000000.

The previous prime is 131319999959. The next prime is 131320000003. The reversal of 131320000000 is 23131.

It is a Harshad number since it is a multiple of its sum of digits (10).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131320000003) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1959999967 + ... + 1960000033.

Almost surely, 2131320000000 is an apocalyptic number.

131320000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131320000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (193610246544).

131320000000 is an abundant number, since it is smaller than the sum of its proper divisors (255900493088).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131320000000 is an frugal number, since it uses more digits than its factorization.

131320000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 134 (or 81 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 10.

Adding to 131320000000 its reverse (23131), we get a palindrome (131320023131).

The spelling of 131320000000 in words is "one hundred thirty-one billion, three hundred twenty million", and thus it is an aban number.