Base | Representation |
---|---|
bin | 11101110110111101010010… |
… | …100011100111001000100111 |
3 | 122012222001220021222021210111 |
4 | 131312331102203213020213 |
5 | 114203021340044022442 |
6 | 1143143325124233451 |
7 | 36442362161611243 |
oct | 3566752243471047 |
9 | 565861807867714 |
10 | 131320010142247 |
11 | 3892a55a246463 |
12 | 1288a84583b887 |
13 | 5837568198784 |
14 | 245dccb10d423 |
15 | 102ae0508eb17 |
hex | 776f528e7227 |
131320010142247 has 2 divisors, whose sum is σ = 131320010142248. Its totient is φ = 131320010142246.
The previous prime is 131320010142193. The next prime is 131320010142271. The reversal of 131320010142247 is 742241010023131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131320010142247 - 231 = 131317862658599 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131320010148247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65660005071123 + 65660005071124.
It is an arithmetic number, because the mean of its divisors is an integer number (65660005071124).
Almost surely, 2131320010142247 is an apocalyptic number.
131320010142247 is a deficient number, since it is larger than the sum of its proper divisors (1).
131320010142247 is an equidigital number, since it uses as much as digits as its factorization.
131320010142247 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8064, while the sum is 31.
Adding to 131320010142247 its reverse (742241010023131), we get a palindrome (873561020165378).
The spelling of 131320010142247 in words is "one hundred thirty-one trillion, three hundred twenty billion, ten million, one hundred forty-two thousand, two hundred forty-seven".
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