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13132001665113 = 34377333888371
BaseRepresentation
bin1011111100011000100001…
…0010110110000001011001
31201111101222202220220020020
42333012020102312001121
53210123314411240423
643532431442221053
72523520146264162
oct277061022660131
951441882826206
1013132001665113
114203283653511
1215810a0954789
1374345b46b176
143358412a0769
1517b8d80db4e3
hexbf1884b6059

13132001665113 has 4 divisors (see below), whose sum is σ = 17509335553488. Its totient is φ = 8754667776740.

The previous prime is 13132001665103. The next prime is 13132001665121. The reversal of 13132001665113 is 31156610023131.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13132001665113 - 28 = 13132001664857 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13132001665103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2188666944183 + ... + 2188666944188.

It is an arithmetic number, because the mean of its divisors is an integer number (4377333888372).

Almost surely, 213132001665113 is an apocalyptic number.

It is an amenable number.

13132001665113 is a deficient number, since it is larger than the sum of its proper divisors (4377333888375).

13132001665113 is an equidigital number, since it uses as much as digits as its factorization.

13132001665113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4377333888374.

The product of its (nonzero) digits is 9720, while the sum is 33.

Adding to 13132001665113 its reverse (31156610023131), we get a palindrome (44288611688244).

The spelling of 13132001665113 in words is "thirteen trillion, one hundred thirty-two billion, one million, six hundred sixty-five thousand, one hundred thirteen".

Divisors: 1 3 4377333888371 13132001665113