Base | Representation |
---|---|
bin | 10011000111000000111… |
… | …000101001100100111101 |
3 | 11122112121020112212120011 |
4 | 103013000320221210331 |
5 | 133003413440213432 |
6 | 2443135401023221 |
7 | 163606230120553 |
oct | 23070070514475 |
9 | 4575536485504 |
10 | 1313201101117 |
11 | 466a1a871914 |
12 | 192610484b11 |
13 | 96ab004a689 |
14 | 477b8901bd3 |
15 | 2425cd4c847 |
hex | 131c0e2993d |
1313201101117 has 2 divisors, whose sum is σ = 1313201101118. Its totient is φ = 1313201101116.
The previous prime is 1313201101063. The next prime is 1313201101129. The reversal of 1313201101117 is 7111011023131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 755350453881 + 557850647236 = 869109^2 + 746894^2 .
It is a cyclic number.
It is not a de Polignac number, because 1313201101117 - 211 = 1313201099069 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1313201101517) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656600550558 + 656600550559.
It is an arithmetic number, because the mean of its divisors is an integer number (656600550559).
Almost surely, 21313201101117 is an apocalyptic number.
It is an amenable number.
1313201101117 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313201101117 is an equidigital number, since it uses as much as digits as its factorization.
1313201101117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 126, while the sum is 22.
Adding to 1313201101117 its reverse (7111011023131), we get a palindrome (8424212124248).
The spelling of 1313201101117 in words is "one trillion, three hundred thirteen billion, two hundred one million, one hundred one thousand, one hundred seventeen".
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