Base | Representation |
---|---|
bin | 10011000111000000111… |
… | …001001001010100001111 |
3 | 11122112121020210110220001 |
4 | 103013000321021110033 |
5 | 133003414003343434 |
6 | 2443135403505131 |
7 | 163606231201561 |
oct | 23070071112417 |
9 | 4575536713801 |
10 | 1313201231119 |
11 | 466a1a950558 |
12 | 1926105281a7 |
13 | 96ab00948bb |
14 | 477b8937331 |
15 | 2425cd76114 |
hex | 131c0e4950f |
1313201231119 has 2 divisors, whose sum is σ = 1313201231120. Its totient is φ = 1313201231118.
The previous prime is 1313201231081. The next prime is 1313201231141. The reversal of 1313201231119 is 9111321023131.
It is a strong prime.
It is an emirp because it is prime and its reverse (9111321023131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1313201231119 - 237 = 1175762277647 is a prime.
It is a super-2 number, since 2×13132012311192 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1313201231159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656600615559 + 656600615560.
It is an arithmetic number, because the mean of its divisors is an integer number (656600615560).
Almost surely, 21313201231119 is an apocalyptic number.
1313201231119 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313201231119 is an equidigital number, since it uses as much as digits as its factorization.
1313201231119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 28.
The spelling of 1313201231119 in words is "one trillion, three hundred thirteen billion, two hundred one million, two hundred thirty-one thousand, one hundred nineteen".
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