1313203313137 has 2 divisors, whose sum is σ = 1313203313138. Its totient is φ = 1313203313136.

The previous prime is 1313203313117. The next prime is 1313203313203. The reversal of 1313203313137 is 7313133023131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1281116114496 + 32087198641 = 1131864^2 + 179129^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1313203313137 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1313203313099 and 1313203313108.

It is not a weakly prime, because it can be changed into another prime (1313203313117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656601656568 + 656601656569.

It is an arithmetic number, because the mean of its divisors is an integer number (656601656569).

Almost surely, 2^{1313203313137} is an apocalyptic number.

It is an amenable number.

1313203313137 is a deficient number, since it is larger than the sum of its proper divisors (1).

1313203313137 is an equidigital number, since it uses as much as digits as its factorization.

1313203313137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10206, while the sum is 31.

Adding to 1313203313137 its reverse (7313133023131), we get a palindrome (8626336336268).

The spelling of 1313203313137 in words is "one trillion, three hundred thirteen billion, two hundred three million, three hundred thirteen thousand, one hundred thirty-seven".