Base | Representation |
---|---|
bin | 10011000111000001011… |
… | …010111110111001000001 |
3 | 11122112121212111010111202 |
4 | 103013001122332321001 |
5 | 133003423241220223 |
6 | 2443140321550545 |
7 | 163606366454315 |
oct | 23070132767101 |
9 | 4575555433452 |
10 | 1313210101313 |
11 | 466a249598a0 |
12 | 1926134a5455 |
13 | 96ab1b7c136 |
14 | 477b9ba5b45 |
15 | 2425da29428 |
hex | 131c16bee41 |
1313210101313 has 4 divisors (see below), whose sum is σ = 1432592837808. Its totient is φ = 1193827364820.
The previous prime is 1313210101297. The next prime is 1313210101331. The reversal of 1313210101313 is 3131010123131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1313210101313 - 24 = 1313210101297 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1313210101373) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59691368231 + ... + 59691368252.
It is an arithmetic number, because the mean of its divisors is an integer number (358148209452).
Almost surely, 21313210101313 is an apocalyptic number.
It is an amenable number.
1313210101313 is a deficient number, since it is larger than the sum of its proper divisors (119382736495).
1313210101313 is a wasteful number, since it uses less digits than its factorization.
1313210101313 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 119382736494.
The product of its (nonzero) digits is 162, while the sum is 20.
Adding to 1313210101313 its reverse (3131010123131), we get a palindrome (4444220224444).
The spelling of 1313210101313 in words is "one trillion, three hundred thirteen billion, two hundred ten million, one hundred one thousand, three hundred thirteen".
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