13132101121201 has 4 divisors (see below), whose sum is σ = 13132302072304. Its totient is φ = 13131900170100.

The previous prime is 13132101121127. The next prime is 13132101121219. The reversal of 13132101121201 is 10212110123131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13132101121201 - 2¹³ = 13132101113009 is a prime.

It is a super-3 number, since 3×13132101121201³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13132101121001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 100377495 + ... + 100508236.

It is an arithmetic number, because the mean of its divisors is an integer number (3283075518076).

Almost surely, 2^{13132101121201} is an apocalyptic number.

It is an amenable number.

13132101121201 is a deficient number, since it is larger than the sum of its proper divisors (200951103).

13132101121201 is an equidigital number, since it uses as much as digits as its factorization.

13132101121201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 200951102.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 13132101121201 its reverse (10212110123131), we get a palindrome (23344211244332).

The spelling of 13132101121201 in words is "thirteen trillion, one hundred thirty-two billion, one hundred one million, one hundred twenty-one thousand, two hundred one".