Base | Representation |
---|---|
bin | 1011111100011000111111… |
… | …1100111001110000000011 |
3 | 1201111102022201122122020002 |
4 | 2333012033330321300003 |
5 | 3210124100303142242 |
6 | 43532452311510215 |
7 | 2523523266235142 |
oct | 277061774716003 |
9 | 51442281578202 |
10 | 13132130130947 |
11 | 420333a117823 |
12 | 158111798836b |
13 | 74347bc6a559 |
14 | 335854381759 |
15 | 17b8e4515432 |
hex | bf18ff39c03 |
13132130130947 has 2 divisors, whose sum is σ = 13132130130948. Its totient is φ = 13132130130946.
The previous prime is 13132130130913. The next prime is 13132130131009. The reversal of 13132130130947 is 74903103123131.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13132130130947 - 212 = 13132130126851 is a prime.
It is a super-2 number, since 2×131321301309472 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13132130130947.
It is not a weakly prime, because it can be changed into another prime (13132130130247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6566065065473 + 6566065065474.
It is an arithmetic number, because the mean of its divisors is an integer number (6566065065474).
Almost surely, 213132130130947 is an apocalyptic number.
13132130130947 is a deficient number, since it is larger than the sum of its proper divisors (1).
13132130130947 is an equidigital number, since it uses as much as digits as its factorization.
13132130130947 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 40824, while the sum is 38.
The spelling of 13132130130947 in words is "thirteen trillion, one hundred thirty-two billion, one hundred thirty million, one hundred thirty thousand, nine hundred forty-seven".
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