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131322200441 = 253987517043
BaseRepresentation
bin111101001001101101…
…0011100000101111001
3110112222001212222122112
41322103122130011321
54122421440403231
6140154550302105
712326200200065
oct1722332340571
9415861788575
10131322200441
1150769a5a973
122154b657935
13c4caab3663
1464dad28aa5
153638e8b92b
hex1e9369c179

131322200441 has 4 divisors (see below), whose sum is σ = 131322971472. Its totient is φ = 131321429412.

The previous prime is 131322200419. The next prime is 131322200453. The reversal of 131322200441 is 144002223131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 131322200441 - 214 = 131322184057 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131322200411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4535 + ... + 512508.

It is an arithmetic number, because the mean of its divisors is an integer number (32830742868).

Almost surely, 2131322200441 is an apocalyptic number.

It is an amenable number.

131322200441 is a deficient number, since it is larger than the sum of its proper divisors (771031).

131322200441 is an equidigital number, since it uses as much as digits as its factorization.

131322200441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 771030.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 131322200441 its reverse (144002223131), we get a palindrome (275324423572).

The spelling of 131322200441 in words is "one hundred thirty-one billion, three hundred twenty-two million, two hundred thousand, four hundred forty-one".

Divisors: 1 253987 517043 131322200441