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13132232121134 = 272134002368583
BaseRepresentation
bin1011111100011001011000…
…0001111101101100101110
31201111102120211120021110102
42333012112001331230232
53210124302410334014
643532510353511102
72523525645156500
oct277062601755456
951442524507412
1013132232121134
114203391748535
121581145b72492
13743497129b89
14335863b2dd70
1517b8ed45e8de
hexbf19607db2e

13132232121134 has 12 divisors (see below), whose sum is σ = 22914405027864. Its totient is φ = 5628099480444.

The previous prime is 13132232121119. The next prime is 13132232121181. The reversal of 13132232121134 is 43112123223131.

It is a junction number, because it is equal to n+sod(n) for n = 13132232121097 and 13132232121106.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 67001184194 + ... + 67001184389.

It is an arithmetic number, because the mean of its divisors is an integer number (1909533752322).

Almost surely, 213132232121134 is an apocalyptic number.

13132232121134 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

13132232121134 is a deficient number, since it is larger than the sum of its proper divisors (9782172906730).

13132232121134 is a wasteful number, since it uses less digits than its factorization.

13132232121134 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 134002368599 (or 134002368592 counting only the distinct ones).

The product of its digits is 5184, while the sum is 29.

Adding to 13132232121134 its reverse (43112123223131), we get a palindrome (56244355344265).

The spelling of 13132232121134 in words is "thirteen trillion, one hundred thirty-two billion, two hundred thirty-two million, one hundred twenty-one thousand, one hundred thirty-four".

Divisors: 1 2 7 14 49 98 134002368583 268004737166 938016580081 1876033160162 6566116060567 13132232121134