Base | Representation |
---|---|
bin | 1011111100011001011010… |
… | …0101011110011010010011 |
3 | 1201111102121111002020001021 |
4 | 2333012112211132122103 |
5 | 3210124312301231123 |
6 | 43532511325220311 |
7 | 2523526120250512 |
oct | 277062645363223 |
9 | 51442544066037 |
10 | 13132241430163 |
11 | 4203396a26549 |
12 | 1581149101697 |
13 | 74349903908b |
14 | 335865074679 |
15 | 17b8ee19cc5d |
hex | bf19695e693 |
13132241430163 has 2 divisors, whose sum is σ = 13132241430164. Its totient is φ = 13132241430162.
The previous prime is 13132241430151. The next prime is 13132241430197. The reversal of 13132241430163 is 36103414223131.
It is an a-pointer prime, because the next prime (13132241430197) can be obtained adding 13132241430163 to its sum of digits (34).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13132241430163 - 221 = 13132239333011 is a prime.
It is not a weakly prime, because it can be changed into another prime (13132241434163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6566120715081 + 6566120715082.
It is an arithmetic number, because the mean of its divisors is an integer number (6566120715082).
Almost surely, 213132241430163 is an apocalyptic number.
13132241430163 is a deficient number, since it is larger than the sum of its proper divisors (1).
13132241430163 is an equidigital number, since it uses as much as digits as its factorization.
13132241430163 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 31104, while the sum is 34.
Adding to 13132241430163 its reverse (36103414223131), we get a palindrome (49235655653294).
The spelling of 13132241430163 in words is "thirteen trillion, one hundred thirty-two billion, two hundred forty-one million, four hundred thirty thousand, one hundred sixty-three".
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