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13132242169 is a prime number
BaseRepresentation
bin11000011101011111…
…00001110011111001
31020220012122000121121
430032233201303321
5203343323222134
610011033305241
7643300134214
oct141657416371
936805560547
1013132242169
115629898a02
122665b65221
1313138c3bc7
148c815077b
1551cd74ab4
hex30ebe1cf9

13132242169 has 2 divisors, whose sum is σ = 13132242170. Its totient is φ = 13132242168.

The previous prime is 13132242163. The next prime is 13132242203. The reversal of 13132242169 is 96124223131.

It is an a-pointer prime, because the next prime (13132242203) can be obtained adding 13132242169 to its sum of digits (34).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12407286544 + 724955625 = 111388^2 + 26925^2 .

It is an emirp because it is prime and its reverse (96124223131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13132242169 is a prime.

It is a super-2 number, since 2×131322421692 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13132242163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6566121084 + 6566121085.

It is an arithmetic number, because the mean of its divisors is an integer number (6566121085).

Almost surely, 213132242169 is an apocalyptic number.

It is an amenable number.

13132242169 is a deficient number, since it is larger than the sum of its proper divisors (1).

13132242169 is an equidigital number, since it uses as much as digits as its factorization.

13132242169 is an evil number, because the sum of its binary digits is even.

The product of its digits is 15552, while the sum is 34.

The spelling of 13132242169 in words is "thirteen billion, one hundred thirty-two million, two hundred forty-two thousand, one hundred sixty-nine".