Base | Representation |
---|---|
bin | 111101001001101101… |
… | …1010010110000001111 |
3 | 110112222002022100202220 |
4 | 1322103123102300033 |
5 | 4122422020034320 |
6 | 140154555150423 |
7 | 12326202121614 |
oct | 1722333226017 |
9 | 415862270686 |
10 | 131322424335 |
11 | 5076a0a3103 |
12 | 2154b745413 |
13 | c4cab6153b |
14 | 64dad8650b |
15 | 3638ed2e40 |
hex | 1e936d2c0f |
131322424335 has 16 divisors (see below), whose sum is σ = 211404937344. Its totient is φ = 69608940192.
The previous prime is 131322424271. The next prime is 131322424349. The reversal of 131322424335 is 533424223131.
It is not a de Polignac number, because 131322424335 - 26 = 131322424271 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131322424296 and 131322424305.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 26852857 + ... + 26857746.
It is an arithmetic number, because the mean of its divisors is an integer number (13212808584).
Almost surely, 2131322424335 is an apocalyptic number.
131322424335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
131322424335 is a deficient number, since it is larger than the sum of its proper divisors (80082513009).
131322424335 is a wasteful number, since it uses less digits than its factorization.
131322424335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 53710774.
The product of its digits is 51840, while the sum is 33.
Adding to 131322424335 its reverse (533424223131), we get a palindrome (664746647466).
The spelling of 131322424335 in words is "one hundred thirty-one billion, three hundred twenty-two million, four hundred twenty-four thousand, three hundred thirty-five".
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