Base | Representation |
---|---|
bin | 10011000111000010010… |
… | …000111011100011000001 |
3 | 11122112122212002121210111 |
4 | 103013002100323203001 |
5 | 133003440401242033 |
6 | 2443141545031321 |
7 | 163606630615006 |
oct | 23070220734301 |
9 | 4575585077714 |
10 | 1313224243393 |
11 | 466a31938a67 |
12 | 192618185541 |
13 | 96ab4a9112a |
14 | 477bba078ad |
15 | 2425edbe7cd |
hex | 131c243b8c1 |
1313224243393 has 2 divisors, whose sum is σ = 1313224243394. Its totient is φ = 1313224243392.
The previous prime is 1313224243349. The next prime is 1313224243423. The reversal of 1313224243393 is 3933424223131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 916063380544 + 397160862849 = 957112^2 + 630207^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1313224243393 is a prime.
It is not a weakly prime, because it can be changed into another prime (1313224243343) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656612121696 + 656612121697.
It is an arithmetic number, because the mean of its divisors is an integer number (656612121697).
Almost surely, 21313224243393 is an apocalyptic number.
It is an amenable number.
1313224243393 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313224243393 is an equidigital number, since it uses as much as digits as its factorization.
1313224243393 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 279936, while the sum is 40.
The spelling of 1313224243393 in words is "one trillion, three hundred thirteen billion, two hundred twenty-four million, two hundred forty-three thousand, three hundred ninety-three".
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