Base | Representation |
---|---|
bin | 1011111100011001011010… |
… | …1100011001000110010010 |
3 | 1201111102121121111100100120 |
4 | 2333012112230121012102 |
5 | 3210124313232242120 |
6 | 43532511432131110 |
7 | 2523526141542114 |
oct | 277062654310622 |
9 | 51442547440316 |
10 | 13132243243410 |
11 | 4203397a548a5 |
12 | 1581149836a96 |
13 | 7434995224c5 |
14 | 3358653c73b4 |
15 | 17b8ee40a140 |
hex | bf196b19192 |
13132243243410 has 32 divisors (see below), whose sum is σ = 31519267636032. Its totient is φ = 3501722214720.
The previous prime is 13132243243393. The next prime is 13132243243439. The reversal of 13132243243410 is 1434234223131.
13132243243410 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12571704 + ... + 13576163.
It is an arithmetic number, because the mean of its divisors is an integer number (984977113626).
Almost surely, 213132243243410 is an apocalyptic number.
13132243243410 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13132243243410 is an abundant number, since it is smaller than the sum of its proper divisors (18387024392622).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13132243243410 is a wasteful number, since it uses less digits than its factorization.
13132243243410 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26164618.
The product of its (nonzero) digits is 41472, while the sum is 33.
Adding to 13132243243410 its reverse (1434234223131), we get a palindrome (14566477466541).
The spelling of 13132243243410 in words is "thirteen trillion, one hundred thirty-two billion, two hundred forty-three million, two hundred forty-three thousand, four hundred ten".
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