Base | Representation |
---|---|
bin | 10011000111000010100… |
… | …111010001101011100111 |
3 | 11122112200021010020020011 |
4 | 103013002213101223213 |
5 | 133003443401214343 |
6 | 2443142314351051 |
7 | 163610031453145 |
oct | 23070247215347 |
9 | 4575607106204 |
10 | 1313230101223 |
11 | 466a3517a047 |
12 | 19261a12b487 |
13 | 96ab60624c1 |
14 | 477bc6d0595 |
15 | 2426067a29d |
hex | 131c29d1ae7 |
1313230101223 has 2 divisors, whose sum is σ = 1313230101224. Its totient is φ = 1313230101222.
The previous prime is 1313230101179. The next prime is 1313230101247. The reversal of 1313230101223 is 3221010323131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1313230101223 - 213 = 1313230093031 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1313230101194 and 1313230101203.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1313230101263) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656615050611 + 656615050612.
It is an arithmetic number, because the mean of its divisors is an integer number (656615050612).
Almost surely, 21313230101223 is an apocalyptic number.
1313230101223 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313230101223 is an equidigital number, since it uses as much as digits as its factorization.
1313230101223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 1313230101223 its reverse (3221010323131), we get a palindrome (4534240424354).
The spelling of 1313230101223 in words is "one trillion, three hundred thirteen billion, two hundred thirty million, one hundred one thousand, two hundred twenty-three".
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