131323321100339 has 2 divisors, whose sum is σ = 131323321100340. Its totient is φ = 131323321100338.

The previous prime is 131323321100203. The next prime is 131323321100341. The reversal of 131323321100339 is 933001123323131.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131323321100339 is a prime.

Together with 131323321100341, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 131323321100299 and 131323321100308.

It is not a weakly prime, because it can be changed into another prime (131323321102339) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65661660550169 + 65661660550170.

It is an arithmetic number, because the mean of its divisors is an integer number (65661660550170).

Almost surely, 2^{131323321100339} is an apocalyptic number.

131323321100339 is a deficient number, since it is larger than the sum of its proper divisors (1).

131323321100339 is an equidigital number, since it uses as much as digits as its factorization.

131323321100339 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 26244, while the sum is 35.

The spelling of 131323321100339 in words is "one hundred thirty-one trillion, three hundred twenty-three billion, three hundred twenty-one million, one hundred thousand, three hundred thirty-nine".