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1313233483169 is a prime number
BaseRepresentation
bin10011000111000010110…
…100001011010110100001
311122112200111111001101102
4103013002310023112201
5133004000232430134
62443142515044145
7163610102300066
oct23070264132641
94575614431342
101313233483169
11466a37079a43
1219261b2a0655
1396ab697795a
14477bcd30c6d
1524260ae737e
hex131c2d0b5a1

1313233483169 has 2 divisors, whose sum is σ = 1313233483170. Its totient is φ = 1313233483168.

The previous prime is 1313233483141. The next prime is 1313233483181. The reversal of 1313233483169 is 9613843323131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1251400195600 + 61833287569 = 1118660^2 + 248663^2 .

It is a cyclic number.

It is not a de Polignac number, because 1313233483169 - 220 = 1313232434593 is a prime.

It is a super-2 number, since 2×13132334831692 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1313233483109) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656616741584 + 656616741585.

It is an arithmetic number, because the mean of its divisors is an integer number (656616741585).

Almost surely, 21313233483169 is an apocalyptic number.

It is an amenable number.

1313233483169 is a deficient number, since it is larger than the sum of its proper divisors (1).

1313233483169 is an equidigital number, since it uses as much as digits as its factorization.

1313233483169 is an evil number, because the sum of its binary digits is even.

The product of its digits is 839808, while the sum is 47.

The spelling of 1313233483169 in words is "one trillion, three hundred thirteen billion, two hundred thirty-three million, four hundred eighty-three thousand, one hundred sixty-nine".