Base | Representation |
---|---|
bin | 10011000111000010110… |
… | …100001011010110100001 |
3 | 11122112200111111001101102 |
4 | 103013002310023112201 |
5 | 133004000232430134 |
6 | 2443142515044145 |
7 | 163610102300066 |
oct | 23070264132641 |
9 | 4575614431342 |
10 | 1313233483169 |
11 | 466a37079a43 |
12 | 19261b2a0655 |
13 | 96ab697795a |
14 | 477bcd30c6d |
15 | 24260ae737e |
hex | 131c2d0b5a1 |
1313233483169 has 2 divisors, whose sum is σ = 1313233483170. Its totient is φ = 1313233483168.
The previous prime is 1313233483141. The next prime is 1313233483181. The reversal of 1313233483169 is 9613843323131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1251400195600 + 61833287569 = 1118660^2 + 248663^2 .
It is a cyclic number.
It is not a de Polignac number, because 1313233483169 - 220 = 1313232434593 is a prime.
It is a super-2 number, since 2×13132334831692 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1313233483109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656616741584 + 656616741585.
It is an arithmetic number, because the mean of its divisors is an integer number (656616741585).
Almost surely, 21313233483169 is an apocalyptic number.
It is an amenable number.
1313233483169 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313233483169 is an equidigital number, since it uses as much as digits as its factorization.
1313233483169 is an evil number, because the sum of its binary digits is even.
The product of its digits is 839808, while the sum is 47.
The spelling of 1313233483169 in words is "one trillion, three hundred thirteen billion, two hundred thirty-three million, four hundred eighty-three thousand, one hundred sixty-nine".
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