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1313233483181 is a prime number
BaseRepresentation
bin10011000111000010110…
…100001011010110101101
311122112200111111001101212
4103013002310023112231
5133004000232430211
62443142515044205
7163610102300114
oct23070264132655
94575614431355
101313233483181
11466a37079a54
1219261b2a0665
1396ab6977969
14477bcd30c7b
1524260ae738b
hex131c2d0b5ad

1313233483181 has 2 divisors, whose sum is σ = 1313233483182. Its totient is φ = 1313233483180.

The previous prime is 1313233483169. The next prime is 1313233483187. The reversal of 1313233483181 is 1813843323131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1027151845225 + 286081637956 = 1013485^2 + 534866^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1313233483181 is a prime.

It is a super-2 number, since 2×13132334831812 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1313233483187) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656616741590 + 656616741591.

It is an arithmetic number, because the mean of its divisors is an integer number (656616741591).

Almost surely, 21313233483181 is an apocalyptic number.

It is an amenable number.

1313233483181 is a deficient number, since it is larger than the sum of its proper divisors (1).

1313233483181 is an equidigital number, since it uses as much as digits as its factorization.

1313233483181 is an evil number, because the sum of its binary digits is even.

The product of its digits is 124416, while the sum is 41.

The spelling of 1313233483181 in words is "one trillion, three hundred thirteen billion, two hundred thirty-three million, four hundred eighty-three thousand, one hundred eighty-one".