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131324444597 is a prime number
BaseRepresentation
bin111101001001110001…
…0111111111110110101
3110112222020010000001102
41322103202333332311
54122423024211342
6140155110335445
712326225234603
oct1722342777665
9415866100042
10131324444597
1150770252a45
122155035a585
13c4cb3bac68
1464db350873
153639281832
hex1e938bffb5

131324444597 has 2 divisors, whose sum is σ = 131324444598. Its totient is φ = 131324444596.

The previous prime is 131324444569. The next prime is 131324444609. The reversal of 131324444597 is 795444423131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 108630227281 + 22694217316 = 329591^2 + 150646^2 .

It is a cyclic number.

It is not a de Polignac number, because 131324444597 - 28 = 131324444341 is a prime.

It is a super-2 number, since 2×1313244445972 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131324441597) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65662222298 + 65662222299.

It is an arithmetic number, because the mean of its divisors is an integer number (65662222299).

Almost surely, 2131324444597 is an apocalyptic number.

It is an amenable number.

131324444597 is a deficient number, since it is larger than the sum of its proper divisors (1).

131324444597 is an equidigital number, since it uses as much as digits as its factorization.

131324444597 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1451520, while the sum is 47.

The spelling of 131324444597 in words is "one hundred thirty-one billion, three hundred twenty-four million, four hundred forty-four thousand, five hundred ninety-seven".