Base | Representation |
---|---|
bin | 111101001001110001… |
… | …1010000010100100011 |
3 | 110112222020020101212011 |
4 | 1322103203100110203 |
5 | 4122423033332043 |
6 | 140155112013351 |
7 | 12326225633662 |
oct | 1722343202443 |
9 | 415866211764 |
10 | 131324511523 |
11 | 50770299257 |
12 | 21550391257 |
13 | c4cb41256a |
14 | 64db36add9 |
15 | 363929659d |
hex | 1e938d0523 |
131324511523 has 2 divisors, whose sum is σ = 131324511524. Its totient is φ = 131324511522.
The previous prime is 131324511511. The next prime is 131324511541. The reversal of 131324511523 is 325115423131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131324511523 - 25 = 131324511491 is a prime.
It is a super-2 number, since 2×1313245115232 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131324511583) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65662255761 + 65662255762.
It is an arithmetic number, because the mean of its divisors is an integer number (65662255762).
Almost surely, 2131324511523 is an apocalyptic number.
131324511523 is a deficient number, since it is larger than the sum of its proper divisors (1).
131324511523 is an equidigital number, since it uses as much as digits as its factorization.
131324511523 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 10800, while the sum is 31.
Adding to 131324511523 its reverse (325115423131), we get a palindrome (456439934654).
The spelling of 131324511523 in words is "one hundred thirty-one billion, three hundred twenty-four million, five hundred eleven thousand, five hundred twenty-three".
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