Base | Representation |
---|---|
bin | 111101001001110001… |
… | …1010010110001000111 |
3 | 110112222020020220121021 |
4 | 1322103203102301013 |
5 | 4122423034142133 |
6 | 140155112132011 |
7 | 12326226005125 |
oct | 1722343226107 |
9 | 415866226537 |
10 | 131324521543 |
11 | 507702a5836 |
12 | 21550397007 |
13 | c4cb416ca7 |
14 | 64db370915 |
15 | 363929952d |
hex | 1e938d2c47 |
131324521543 has 2 divisors, whose sum is σ = 131324521544. Its totient is φ = 131324521542.
The previous prime is 131324521511. The next prime is 131324521553. The reversal of 131324521543 is 345125423131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131324521543 - 25 = 131324521511 is a prime.
It is a super-2 number, since 2×1313245215432 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 131324521499 and 131324521508.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131324521553) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65662260771 + 65662260772.
It is an arithmetic number, because the mean of its divisors is an integer number (65662260772).
Almost surely, 2131324521543 is an apocalyptic number.
131324521543 is a deficient number, since it is larger than the sum of its proper divisors (1).
131324521543 is an equidigital number, since it uses as much as digits as its factorization.
131324521543 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 43200, while the sum is 34.
Adding to 131324521543 its reverse (345125423131), we get a palindrome (476449944674).
The spelling of 131324521543 in words is "one hundred thirty-one billion, three hundred twenty-four million, five hundred twenty-one thousand, five hundred forty-three".
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