13132533240245 has 16 divisors (see below), whose sum is σ = 15775168514160. Its totient is φ = 10495279641600.

The previous prime is 13132533240241. The next prime is 13132533240301. The reversal of 13132533240245 is 54204233523131.

It can be written as a sum of positive squares in 8 ways, for example, as 457637367121 + 12674895873124 = 676489^2 + 3560182^2 .

It is not a de Polignac number, because 13132533240245 - 2² = 13132533240241 is a prime.

It is a super-2 number, since 2×13132533240245² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13132533240199 and 13132533240208.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13132533240241) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 18990455 + ... + 19669835.

It is an arithmetic number, because the mean of its divisors is an integer number (985948032135).

Almost surely, 2^{13132533240245} is an apocalyptic number.

It is an amenable number.

13132533240245 is a deficient number, since it is larger than the sum of its proper divisors (2642635273915).

13132533240245 is a wasteful number, since it uses less digits than its factorization.

13132533240245 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 683336.

The product of its (nonzero) digits is 259200, while the sum is 38.

Adding to 13132533240245 its reverse (54204233523131), we get a palindrome (67336766763376).

The spelling of 13132533240245 in words is "thirteen trillion, one hundred thirty-two billion, five hundred thirty-three million, two hundred forty thousand, two hundred forty-five".