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13132550023 = 65919927997
BaseRepresentation
bin11000011101100001…
…01100111110000111
31020220020012122220121
430032300230332013
5203343413100043
610011044042411
7643302555565
oct141660547607
936806178817
1013132550023
115629a8922a
122666093407
1313139a1078
148c81d0a35
1551cdd5ded
hex30ec2cf87

13132550023 has 4 divisors (see below), whose sum is σ = 13152478680. Its totient is φ = 13112621368.

The previous prime is 13132549981. The next prime is 13132550027. The reversal of 13132550023 is 32005523131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 32005523131 = 157920269489.

It is a cyclic number.

It is not a de Polignac number, because 13132550023 - 221 = 13130452871 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13132550023.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13132550027) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9963340 + ... + 9964657.

It is an arithmetic number, because the mean of its divisors is an integer number (3288119670).

Almost surely, 213132550023 is an apocalyptic number.

13132550023 is a deficient number, since it is larger than the sum of its proper divisors (19928657).

13132550023 is an equidigital number, since it uses as much as digits as its factorization.

13132550023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19928656.

The product of its (nonzero) digits is 2700, while the sum is 25.

The spelling of 13132550023 in words is "thirteen billion, one hundred thirty-two million, five hundred fifty thousand, twenty-three".

Divisors: 1 659 19927997 13132550023