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131327124042240 = 29365719529097
BaseRepresentation
bin11101110111000011111010…
…100100111111001000000000
3122012222202021002000212000000
4131313003322210333020000
5114203130422223322430
61143150503052000000
736443033363014410
oct3567037244771000
9565882232025000
10131327124042240
113893257a915855
12128900b0160000
13583812cc70c59
1424603a3c38640
15102b1be8a6e60
hex7770fa93f200

131327124042240 has 1120 divisors, whose sum is σ = 567940904277120. Its totient is φ = 28437699428352.

The previous prime is 131327124042229. The next prime is 131327124042253. The reversal of 131327124042240 is 42240421723131.

131327124042240 is a `hidden beast` number, since 1 + 3 + 1 + 3 + 2 + 7 + 1 + 2 + 404 + 2 + 240 = 666.

It is a tau number, because it is divible by the number of its divisors (1120).

It is a Harshad number since it is a multiple of its sum of digits (36).

It is a junction number, because it is equal to n+sod(n) for n = 131327124042195 and 131327124042204.

It is an unprimeable number.

It is a polite number, since it can be written in 111 ways as a sum of consecutive naturals, for example, 247945372 + ... + 248474468.

Almost surely, 2131327124042240 is an apocalyptic number.

131327124042240 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131327124042240, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (283970452138560).

131327124042240 is an abundant number, since it is smaller than the sum of its proper divisors (436613780234880).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131327124042240 is an frugal number, since it uses more digits than its factorization.

131327124042240 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 529164 (or 529133 counting only the distinct ones).

The product of its (nonzero) digits is 64512, while the sum is 36.

Adding to 131327124042240 its reverse (42240421723131), we get a palindrome (173567545765371).

The spelling of 131327124042240 in words is "one hundred thirty-one trillion, three hundred twenty-seven billion, one hundred twenty-four million, forty-two thousand, two hundred forty".