Base | Representation |
---|---|
bin | 1011111100011100001111… |
… | …0111000010110000011000 |
3 | 1201111111120102100212222020 |
4 | 2333013003313002300120 |
5 | 3210132341224311300 |
6 | 43533114541454440 |
7 | 2523554002466541 |
oct | 277070367026030 |
9 | 51444512325866 |
10 | 13133001010200 |
11 | 420374676a245 |
12 | 158131b571420 |
13 | 74358a509216 |
14 | 3358d7cbb4c8 |
15 | 17b945bdd8a0 |
hex | bf1c3dc2c18 |
13133001010200 has 384 divisors, whose sum is σ = 42569853480000. Its totient is φ = 3345045258240.
The previous prime is 13133001010121. The next prime is 13133001010219. The reversal of 13133001010200 is 201010033131.
13133001010200 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 13133001010200.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 1276406656 + ... + 1276416944.
Almost surely, 213133001010200 is an apocalyptic number.
13133001010200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13133001010200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (21284926740000).
13133001010200 is an abundant number, since it is smaller than the sum of its proper divisors (29436852469800).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13133001010200 is a wasteful number, since it uses less digits than its factorization.
13133001010200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11119 (or 11110 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 13133001010200 its reverse (201010033131), we get a palindrome (13334011043331).
The spelling of 13133001010200 in words is "thirteen trillion, one hundred thirty-three billion, one million, ten thousand, two hundred".
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