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13133002534031 is a prime number
BaseRepresentation
bin1011111100011100001111…
…1100110110110010001111
31201111111120112020022021102
42333013003330312302033
53210132342122042111
643533115034253315
72523554021444312
oct277070374666217
951444515208242
1013133002534031
114203747610106
12158131bb8723b
1374358a9209b3
143358d8196979
1517b945de013b
hexbf1c3f36c8f

13133002534031 has 2 divisors, whose sum is σ = 13133002534032. Its totient is φ = 13133002534030.

The previous prime is 13133002533967. The next prime is 13133002534097. The reversal of 13133002534031 is 13043520033131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13133002534031 - 26 = 13133002533967 is a prime.

It is a super-2 number, since 2×131330025340312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13133002533985 and 13133002534003.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13133002534931) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6566501267015 + 6566501267016.

It is an arithmetic number, because the mean of its divisors is an integer number (6566501267016).

Almost surely, 213133002534031 is an apocalyptic number.

13133002534031 is a deficient number, since it is larger than the sum of its proper divisors (1).

13133002534031 is an equidigital number, since it uses as much as digits as its factorization.

13133002534031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9720, while the sum is 29.

Adding to 13133002534031 its reverse (13043520033131), we get a palindrome (26176522567162).

The spelling of 13133002534031 in words is "thirteen trillion, one hundred thirty-three billion, two million, five hundred thirty-four thousand, thirty-one".