Base | Representation |
---|---|
bin | 1011111100011100001111… |
… | …1100110110110010001111 |
3 | 1201111111120112020022021102 |
4 | 2333013003330312302033 |
5 | 3210132342122042111 |
6 | 43533115034253315 |
7 | 2523554021444312 |
oct | 277070374666217 |
9 | 51444515208242 |
10 | 13133002534031 |
11 | 4203747610106 |
12 | 158131bb8723b |
13 | 74358a9209b3 |
14 | 3358d8196979 |
15 | 17b945de013b |
hex | bf1c3f36c8f |
13133002534031 has 2 divisors, whose sum is σ = 13133002534032. Its totient is φ = 13133002534030.
The previous prime is 13133002533967. The next prime is 13133002534097. The reversal of 13133002534031 is 13043520033131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13133002534031 - 26 = 13133002533967 is a prime.
It is a super-2 number, since 2×131330025340312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13133002533985 and 13133002534003.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13133002534931) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6566501267015 + 6566501267016.
It is an arithmetic number, because the mean of its divisors is an integer number (6566501267016).
Almost surely, 213133002534031 is an apocalyptic number.
13133002534031 is a deficient number, since it is larger than the sum of its proper divisors (1).
13133002534031 is an equidigital number, since it uses as much as digits as its factorization.
13133002534031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9720, while the sum is 29.
Adding to 13133002534031 its reverse (13043520033131), we get a palindrome (26176522567162).
The spelling of 13133002534031 in words is "thirteen trillion, one hundred thirty-three billion, two million, five hundred thirty-four thousand, thirty-one".
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