Base | Representation |
---|---|
bin | 111101001001111100… |
… | …0011000110100010111 |
3 | 110112222121122212001222 |
4 | 1322103320120310113 |
5 | 4122430443120401 |
6 | 140155430440555 |
7 | 12326324006042 |
oct | 1722370306427 |
9 | 415877585058 |
10 | 131330051351 |
11 | 50773432424 |
12 | 2155220315b |
13 | c4cc601c75 |
14 | 64dbdadc59 |
15 | 36399dcc1b |
hex | 1e93e18d17 |
131330051351 has 2 divisors, whose sum is σ = 131330051352. Its totient is φ = 131330051350.
The previous prime is 131330051323. The next prime is 131330051371. The reversal of 131330051351 is 153150033131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131330051351 - 214 = 131330034967 is a prime.
It is a super-3 number, since 3×1313300513513 (a number of 34 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 131330051351.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131330051371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65665025675 + 65665025676.
It is an arithmetic number, because the mean of its divisors is an integer number (65665025676).
Almost surely, 2131330051351 is an apocalyptic number.
131330051351 is a deficient number, since it is larger than the sum of its proper divisors (1).
131330051351 is an equidigital number, since it uses as much as digits as its factorization.
131330051351 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2025, while the sum is 26.
Adding to 131330051351 its reverse (153150033131), we get a palindrome (284480084482).
The spelling of 131330051351 in words is "one hundred thirty-one billion, three hundred thirty million, fifty-one thousand, three hundred fifty-one".
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