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131330210131 is a prime number
BaseRepresentation
bin111101001001111100…
…0111111100101010011
3110112222121221220212201
41322103320333211103
54122431013211011
6140155434104031
712326325240001
oct1722370774523
9415877856781
10131330210131
115077353074a
122155227b017
13c4cc659313
1464dc011a71
153639a1ecc1
hex1e93e3f953

131330210131 has 2 divisors, whose sum is σ = 131330210132. Its totient is φ = 131330210130.

The previous prime is 131330210113. The next prime is 131330210147. The reversal of 131330210131 is 131012033131.

Together with previous prime (131330210113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131330210131 - 27 = 131330210003 is a prime.

It is a super-2 number, since 2×1313302101312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131330210099 and 131330210108.

It is not a weakly prime, because it can be changed into another prime (131330210101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65665105065 + 65665105066.

It is an arithmetic number, because the mean of its divisors is an integer number (65665105066).

Almost surely, 2131330210131 is an apocalyptic number.

131330210131 is a deficient number, since it is larger than the sum of its proper divisors (1).

131330210131 is an equidigital number, since it uses as much as digits as its factorization.

131330210131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 131330210131 its reverse (131012033131), we get a palindrome (262342243262).

The spelling of 131330210131 in words is "one hundred thirty-one billion, three hundred thirty million, two hundred ten thousand, one hundred thirty-one".