Base | Representation |
---|---|
bin | 10011000111000110111… |
… | …101010111111101110111 |
3 | 11122112212100022000122221 |
4 | 103013012331113331313 |
5 | 133004121032043444 |
6 | 2443153441103211 |
7 | 163611605223601 |
oct | 23070675277567 |
9 | 4575770260587 |
10 | 1313303002999 |
11 | 466a72342249 |
12 | 19263a627b07 |
13 | 96ac81a8a50 |
14 | 477c826a171 |
15 | 24266c7aa84 |
hex | 131c6f57f77 |
1313303002999 has 16 divisors (see below), whose sum is σ = 1418456368000. Its totient is φ = 1208740942080.
The previous prime is 1313303002961. The next prime is 1313303003017. The reversal of 1313303002999 is 9992003033131.
It is a cyclic number.
It is not a de Polignac number, because 1313303002999 - 217 = 1313302871927 is a prime.
It is a super-3 number, since 3×13133030029993 (a number of 37 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1313303002399) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 27404539 + ... + 27452419.
It is an arithmetic number, because the mean of its divisors is an integer number (88653523000).
Almost surely, 21313303002999 is an apocalyptic number.
1313303002999 is a deficient number, since it is larger than the sum of its proper divisors (105153365001).
1313303002999 is a wasteful number, since it uses less digits than its factorization.
1313303002999 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 54010.
The product of its (nonzero) digits is 118098, while the sum is 43.
The spelling of 1313303002999 in words is "one trillion, three hundred thirteen billion, three hundred three million, two thousand, nine hundred ninety-nine".
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